| ОБРАЗЕЦ РЕШЕНИЯ | К СОДЕРЖАНИЮ |
Вычислить приближённое значение функции
для заданного значения аргумента с помощью дифференциала
| 1 | ![]() | x = 1,012 | 2 | ![]() | x = 0,98 |
| 3 | ![]() | x = 27,54 | 4 | y = arcsin x | x = 0,08 |
| 5 | ![]() | x = 0,97 | 6 | ![]() | x = 26,46 |
| 7 | ![]() | x = 1,97 | 8 | y = x11 | x = 1,021 |
| 9 | ![]() | x = 1,21 | 10 | y = x21 | x = 0,998 |
| 11 | ![]() | x = 1,03 | 12 | y = x6 | x = 2,01 |
| 13 | ![]() | x = 8,24 | 14 | y = x7 | x = 1,996 |
| 15 | ![]() | x = 7,64 | 16 | ![]() | x = 2,56 |
| 17 | ![]() | x = 1,016 | 18 | ![]() | x = 8,36 |
| 19 | ![]() | x = 4,16 | 20 | y = x7 | x = 2,002 |
| 21 | ![]() | x = 1,78 | 22 | ![]() | x = 0,98 |
| 23 | y = x5 | x = 2,997 | 24 | ![]() | x = 1,03 |
| 25 | y = x4 | x = 3,998 | 26 | ![]() | x = 0,01 |
| 27 | ![]() | x = 0,01 | 28 | ![]() | x = 1,02 |
| 29 | ![]() | x = 1,97 | 30 | ![]() | x = 1,58 |
















